Spring rate (spring constant): formula and calculation (Hooke's law)
What the spring rate (k) is, how to calculate it from Hooke's law and the helical spring formula, and how material and dimensions change it.
The spring rate k (also called stiffness) measures how much force a spring needs to deflect one unit of length. It's the single most important property of a spring: it defines whether it is 'stiff' or 'soft'.
Hooke's law
Hooke's law states that, within the elastic range, force is proportional to deflection. The constant of proportionality is k. In a compression spring, compressing 10 mm with k = 5 N/mm takes 50 N.
Helical spring rate formula
For a round-wire helical spring, k depends on the material's shear modulus G, the wire diameter d, the mean diameter D and the number of active coils Na. Note the power: wire diameter enters to the fourth — doubling d multiplies stiffness by 16.
What raises or lowers the rate
- Thicker wire (larger d): raises k strongly (d⁴ effect).
- Larger diameter (larger D): lowers k (1/D³ effect).
- More active coils (larger Na): lowers k proportionally.
- Material: G varies little across steels (~79.3 GPa), more for stainless (~69 GPa).
Worked example
A steel spring (G = 79.3 GPa) with d = 2 mm, D = 18 mm and 6 active coils has k ≈ 79300 · 2⁴ / (8 · 18³ · 6) ≈ 4.5 N/mm. To make it stiffer without changing size, the most efficient path is increasing the wire diameter.
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Frequently asked questions
What is the unit of spring rate?
Usually N/mm (newton per millimetre) for mechanical springs, or N/m in SI. Torsion springs use N·mm per degree.
How do I make a spring stiffer?
The most efficient way is to increase wire diameter (fourth-power effect); reducing coil count or outer diameter also raises k.
Does the rate change with compression?
No, within the linear elastic range k is constant. It only stops holding near solid height or if the material yields.
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